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How Do You Graph Y 2x 1 By Plotting Points Socratic Algebra Graph y=1/2x2 y = − 1 2 x − 2 y = 1 2 x 2 Rewrite in slopeintercept form Tap for more steps The slopeintercept form is y = m x b y = m x b, where m m is the slope and b b is the yintercept y = m x b y = m x b Write in y = m x b y = m x b form Tap for more steps The graph of g(x) = (Onehalf)x is the graph of f(x) = 2x reflected over the yaxis Which graph represents g(x)? Graph y 1/2x 2

29/7/15 color(red)( f(x) = (x2)^21) > The vertex form of a quadratic is given by y = a(x – h)^2 k, where (h, k) is the vertex The "a" in the vertex form is the same "a" as in y = ax^2 bx c Your equation is f(x) = x^24x3 We convert to the "vertex form" by completing the square Step 1 Move the constant to the other side f(x)3 = x^24x Step 2The equation is now solved x^ {2}4x4=y Swap sides so that all variable terms are on the left hand side \left (x2\right)^ {2}=y Factor x^ {2}4x4 In general, when x^ {2}bxc is a perfect square, it can always be factored as \left (x\frac {b} {2}\right)^ {2}Yx^ {2}4x=21 y − x 2 − 4 x = − 2 1 Add 21 to both sides Add 2 1 to both sides yx^ {2}4x21=0 y − x 2 − 4 x 2 1 = 0 All equations of the form ax^ {2}bxc=0 can be solved using the quadratic formula \frac {b±\sqrt {b^ {2}4ac}} {2a} The quadratic formula gives two solutions, one when ± is addition and one when it is Solution Graph The Parabola Y X2 4x 4 Use The Quadratic For